Example
import datetime x = datetime.datetime.today() x #> datetime.datetime(2019, 8, 6, 22, 39, 30, 864393)
The output is in the following order: ‘year’, ‘month’, ‘date’, ‘hour’, ‘minute’, ‘seconds’, ‘microseconds’
Parsing a string to datetime
my_date_time = datetime.datetime.strptime('8/3/19', '%m/%d/%y') my_date_time #> datetime.datetime(2019, 8, 3, 0, 0)
Parsing any string format to datetime
from dateutil.parser import parse parse('94, December 26, 2010, 10:51pm') #> datetime.datetime(1994, 12, 26, 22, 51)
Formatting datetime
my_date_time = datetime.datetime.strptime('8/3/19', '%m/%d/%y') my_date_time.strftime('%m/%d/%y') #> '08/03/19'
Adjusting datetime
my_date_time = datetime.datetime.strptime('8/3/19', '%m/%d/%y') my_date_time - datetime.timedelta(days=2) #> datetime.datetime(2019, 8, 1, 0, 0)
Syntax: datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)
Useful datetime functions
# create a datatime obj dt = datetime.datetime(2019, 2, 15) # 1. Get the current day of the month dt.day #> 31 # 2. Get the current day of the week dt.isoweekday() #> 5 --> Friday # 3. Get the current month of the year dt.month #> 2 --> February # 4. Get the Year dt.year #> 2019
Get the last day of a month for any given date
import datetime dt = datetime.date(1952, 2, 12) import calendar calendar.monthrange(dt.year,dt.month)[1] #> 29
Pandas date_range
import pandas as pd import datetime date1 = pd.Series(pd.date_range('2018-1-1 12:00:00', periods=7, freq='M')) df = pd.DataFrame(dict(date_given=date1)) df
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